C O2

C O2. C(s) + O2(g) > CO2(g) ΔH° = 393 kJ 2CO(g) + O2(g) > 2CO(g) ΔH° = 588 kJ Chemistry 2 Answers Ernest Z Mar 26 2015 The standard enthalpy of formation of carbon monoxide is 99 kJ/mol Our target equation is C(s) +½O₂(g) → CO(g) #ΔH = “?”# We have the following information 1 C(s) + O₂(g) → CO₂(g) #ΔH = “393 kJ”# 2 2CO(g) + O₂ → 2CO₂(g).

CO + O2 = 2CO2 Now having another look we can see that there are two carbons on the right and only one on the left so we have to double that 2CO + O2 = 2CO2 Now we check again and everything balances (with more complicated formulae the ratios are going to vary differently) 54K views View upvotes Related Answer Bob Armstrong.

How to Balance CO + O2 = CO2 YouTube

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How to balance this chemical reaction: C+O2 gives CO+CO2

As the principle repeating unit is carbon itself its formula will be written as C As for the binary combination of oxygen and carbon there are also many different modifications The most important of them are carbonmonooxide ( C O) and carbondioxide ( C O X 2 )20120807.

What is the enthalpy of formation of carbon monoxide in KJ

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